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How many numbers can you form using the digits 1, 5, 6 and 9 without repetition of digits such that the value of the digit 6 in all those number is 100 times the value of the digit 6 in the number 9561?
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How many numbers can you form using the digits 1, 5, 6 and 9 without repetition

of digits such that the value of the digit 6 in all those number is 100 times the
value of the digit 6 in the number 9561?

User MGK
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3.9k points

1 Answer

2 votes

Answer:

D

Explanation:

User JesperSM
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3.8k points
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