Question

If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,

the new volume to the correct number of significant digits is:
O 3 ml
O 12mL
O 24 ml
O 13 ml
O none of these choices

Answer 1

E. None of these

Step-by-step explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

`(P1V1)/(RT1)` =
`(P2V2)/(RT2)`

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

`(1*20)/(R*10) = (10*V2)/(R*100)`

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

`(1*20*100)/(10*10) = V2`

∴ V2 =
`(2000)/(100)`

∴ V2 = 20mL