Question

A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction for 3600.0 seconds. Hint: Draw a position- time graph.

a. Where is the runner at time t= 5.0 s?
b. Where is the runner at time t= 15.0 s?

Answer 1

(a) 25 m

(b) 75 m

Step-by-step explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

`v=(10)/(2)=5m/s\;\cdots(i)`

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So,
`d=vt`

From equation (i)

`\Rightarrow d=5t\;\cdots(ii)`

As the jogger starts from origin, so, the distance,
`d`, also represents the position of the jogger at the time
`t` s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

`d=5* 5=25 m`

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

`d=5* 15=75 m`

So, the jogger is at a distance of 75 m from the origin.