Question

An object moves along a straight line with an initial velocity of 8 m/s with constant acceleration of 0.4m/s^2 for 40 s.

a. what is the velocity at the end of 40 s?

b. What is the distance traveled in this time?

Answer 1

• 24 m/s
• 640 m

Step-by-step explanation:

a) Velocity increased at the rate of 0.40 m/s^2 for 40 s, so increased by ...

(0.40 m/s^2)(40 s) = 16 m/s

The final velocity is ...

8 m/s + 16 m/s = 24 m/s

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b) The average velocity over the 40 s period is (8 m/s +24 m/s)/2 = 16 m/s, so the distance traveled is ...

(16 m/s)(40 s) = 640 m