Question

TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?

SOMEONE HELP I NEED IT ASAP

Answer 1

`x = 5`

`RTV = 74`

Explanation:

Given

`RTV=16x - 6`

`VTS=13x+9`

Required

Determine the values of x and RTV

Since, TV is a bisector, then

`RTS = RTV + VTS` --- (1)

and

`RTV = VTS` -- (2)

Substitute values of RTV and VTS in (2)

`16x - 6 = 13x + 9`

Collect Like Terms

`16x - 13x = 9 + 6`

`3x = 15`

Solve for x

`x = 5`

Substitute 5 for x in
`RTV=16x - 6`

`RTV = 16 * 5 - 6`

`RTV = 80 - 6`

`RTV = 74`