Answer:
![2x+3y=21\\x=2y](https://img.qammunity.org/2021/formulas/mathematics/college/qyl8mbe3mr9j22y4uskhsw9dsovt7zmlvl.png)
x represents the number of two-point shots. y represent the number of three-point shots.
Explanation:
Let's let x represent the number of two-point shots Easton made and let's let y represent the number of three-point shots Easton made.
So, we know that that Easton scored a total of 21 points.
In other words, the amount of two-point shots and amount of three-point shots total 21. In an equation, this is:
![2x+3y=21](https://img.qammunity.org/2021/formulas/mathematics/college/bw5hdbrh00zwl70pjthl11qzzbmlwi9ko6.png)
The 2 in front of the x represents the two-point per shot, and the 3 in front of the y represents the three-point per shot.
We also know that Easton made twice as many two-point shots as three-point shots. So, we can write this as:
![x=2y](https://img.qammunity.org/2021/formulas/mathematics/high-school/fe5pkvpiie29b3p2ze8myimsr8vm55am3w.png)
The number of two-pointers x is equivalent to twice the number of three-pointers y.
So, our system of equations is as follows:
![2x+3y=21\\x=2y](https://img.qammunity.org/2021/formulas/mathematics/college/qyl8mbe3mr9j22y4uskhsw9dsovt7zmlvl.png)
Notes:
To solve, use substitution. Substitute the second equation into the first:
![2(2y)+3y=21](https://img.qammunity.org/2021/formulas/mathematics/college/x4fgo34upod780vkutyc9s8qx0h3dkqv5y.png)
Multiply:
![4y+3y=21](https://img.qammunity.org/2021/formulas/mathematics/college/77pk9ndkillj6xkgkirovnqxgh6yfkdrz6.png)
Combine like terms:
![7y=21](https://img.qammunity.org/2021/formulas/mathematics/high-school/jli7g3tv9n6lrtznwgo59rl6bpf4vcg71h.png)
Divide by 7:
![y=3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v72nrd9c2mqj4ksfbhtnk9xggc28qvnxp2.png)
Solve for x using the second equation again:
![x=2(3)=6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jywdvna9yo46xcnt8lso66ne1e8dr9x7l2.png)
So, Easton made 6 two-pointers and 3 three-pointers.