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Evaluate (4x + y)^2 − 2z for x = 4, y = −2, and z = 6.


(4x + y)^2 − 2z =

1 Answer

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Explanation:

(4x + y)² - 2z = 16x² + 8xy + y² - 2z

substituting x = 4, y = -2 and z = 6,

= 16(4)² + 8(4)(-2) + (-2)² - 2(6)

= 16(16) + 8(-8) + 4 - 12

= 256 - 64 - 8

= 184

=

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