Question

A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?

Answer 1

1/3628800

Explanation:

This question requires that we calculate

1/number of permutations of 10 cities

= P(n,k) = n!/(n-k)!

We have

n = 10

k = 10

= 10!/(10-10)!

= 10!

number of permutations of 10 cities 10! This Is equal to 3,628,800

From this answer we the probability of doing a random tour of these 10 different cities in alphabetical order.

And this is

= 1/3,628,800