Question

A train can speed up at a uniform rate of 0.15 m/s2. In what minimum distance can

it attain a speed of 25 m/s if it is starting from rest?

Answer 1

d = 2083.33 m

Step-by-step explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

`v^2-u^2=2ad\\\\d=(v^2-u^2)/(2a)\\\\d=((25)^2-0)/(2* 0.15)\\\\d=2083.33\ m`

So, the minimum distance is 2083.33 m