Question

In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.75 m and the acceleration achieved during the time the jumper is extending their legs is 1.1 times the acceleration due to gravity,how far can they jump?State your assumptions(increase range can be achieved by swimming the arms in the direction of jump).

Answer 1

0.825 m

Step-by-step explanation:

Given that

Extension of the leg position, s = 0.75 m

Acceleration due to gravity, g = 9.81 m/s²

From the question, it is seen that he accelerated at 1.1 times higher than normal. This means that the acceleration is 1.1 * 9.81.

a = 10.79 m/s²

Now, using one of the equations of motion, we have

v² = u² + 2as, with the initial velocity, u being 0

v² = 2as

v² = 2 * 10.79 * 0.75

v² = 16.185

v = √16.185

v = 4.02 m/s

Next and finally, we find the speed by maximum height

H = (v² - u²)/2g

H = (0 - 4.02²) / (2 * -9.81)

H = -16.185/ -19.62

H = 0.825 m