Answer:
The pressure in Santa Fe, New Mexico is 0.746atm
Step-by-step explanation:
You can solve this question using combined gas law:
P₁V₁ / T₁ = P₂V₂ / T₂
Where P is pressure,
V is volume,
and T is absolute temperature in K for 1, initial state and, final states.
The initial conditions are:
P₁ = 1.01atm
V₁ = 1
T₁ = 21.0°C + 273.15K = 294.15K
And final conditions are:
P₂ = Our unknown
V₂ = 1.4
T₂ = 31.0°C + 273.15K = 304.15K
Replacing:
P₁V₁ / T₁ = P₂V₂ / T₂
1.01atm*1 / 294.15K = P₂*1.4 / 304.15K
P₂ = 0.746atm
The pressure in Santa Fe, New Mexico is 0.746atm