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I need help graphing this

I need help graphing this-example-1
User Dzona
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1 Answer

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Answer: Draw a line through (0,1) and (3,-1)

See diagram below

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Step-by-step explanation:

The given equation y = (-2/3)x+1 is in the form y = mx+b

m = -2/3 is our slope

b = 1 is the y intercept

The y intercept is where the line crosses the vertical y axis. Because b = 1, this location is (0,1). So that's one point we can use to graph this equation.

Another point can be found using the slope

Recall that slope = rise/run

Since slope = -2/3, this means rise/run = -2/3 leading to rise = -2 and run = 3. The "rise = -2" portion tells us to go down 2 and then "run = 3" portion means we go to the right 3 units.

The "down 2, right 3" motion has us go from (0,1) to (3,-1). So (3,-1) is another point we can use. We only need two points to graph a straight line.

The diagram below provides a visual summary. It shows plotting point A as the y intercept, and then you move to point B using the "down 2, right 3" movement rule.

I need help graphing this-example-1
User Mark Micallef
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