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After t seconds the displacement, s(t), of a particle moving rightwards along the x-axis is given (in feet) by

s(t) = 4t^2-5t+3

By determining the average velocity
successively over the time intervals
[1, 1.1], [1, 1.01],

what is a plausible estimate for the instantaneous velocity, v(1), of
the particle at time t = 1.

ANSWER CHOICES:

1. v(1) = 3 ft/sec
2. v(1) = 1 ft/sec
3. v(1) = 4 ft/sec
4. v(1) = 5 ft/sec
5. v(1) = 2 ft/sec

1 Answer

3 votes

Answer:


v(1) = 2\ ft/s

Explanation:

Given


s(t) = 4t^2-5t+3

Required

Determine the instantaneous velocity at
t = 1

First, we need to determine s(1)


s(t) = 4t^2-5t+3


s(1) = 4(1)^2 - 5(1) + 3

Evaluate all brackets


s(1) = 4*1 - 5*1 + 3


s(1) = 4 - 5 + 3


s(1) = 2

Next; v(t) is calculated as thus;


v(t) = (s(t))/(t)

Substitute 1 for t


v(1) = (s(1))/(1)

Substitute 2 for s(t)


v(1) = (2)/(1)


v(1) = 2\ ft/s

User David Conrad
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