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Find cot B if csc ß= 3/5/5 and secß -3/2​

Find cot B if csc ß= 3/5/5 and secß -3/2​-example-1
User RSabet
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1 Answer

21 votes
21 votes

Answer:

A)
\displaystyle (2√(5))/(5)

Explanation:

Since
\csc\beta=(1)/(\sin\beta),
\sec\beta=(1)/(\cos\beta), and
\cot\beta=(\cos\beta)/(\sin\beta), then
\cot\beta=(\csc\beta)/(\sec\beta)

This means that
\displaystyle \cot\beta=(-(3√(5))/(5))/(-(3)/(2))=(-3√(5))/(5)*-(2)/(3)=(2√(5))/(5)

User Xwrs
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