Question

Which graph represents the function f(x) = –x2 + 5? On a coordinate plane, a parabola opens down. It goes through (negative 3, negative 4), has a vertex at (0, 5), and goes through (3, negative 4). On a coordinate plane, a parabola opens up. It goes through (negative 2, 9), has a vertex at (0, 5), and goes through (2, 9). On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 9), has a vertex at (negative 5, 0), and goes through (negative 2, negative 9). On a coordinate plane, a parabola opens up. It goes through (negative 8, 9), has a vertex at (negative 5, 0), and goes through (negative 2, 10).

Answer 1

A on edge

Explanation:

i took the test

Answer 2

The graph in the attached figure

Explanation:

we have the quadratic function

`f(x)=-x^2+5`

This is a vertical parabola open downward

The vertex is a maximum

Remember that

The equation of a vertical parabola in vertex form is equal to

`y=a(x-h)^2+k`

where

a is a coefficient

(h,k) is the vertex

In this problem

a=-1

(h,k)=(0,5) ----> vertex

The y-intercept is the point (0,5) ---> value of y when the value of x is equal to zero (is the same point that the vertex)

The x-intercepts are the points --->values of x when the value of y is equal to zero

using a graphing tool

The graph in the attached figure