Question

3. A model rocket is launched straight upward at 58.8 m/s.

a. How long does it take for the rocket to reach its peak height?

Answer 1

Let us assume that rocket only runs in initial energy and not using its own to flying.

Also , let upward direction is +ve and downward direction is -ve .

Initial velocity , u = 58.8 m/s .

Acceleration due to gravity ,
`g=-9.8\ m/s^2` .

Final velocity , v - = 0 m/s .

We know , by equation of motion .

`v^2-u^2=2gh\\\\2gh_(max)=0^2-58.8^2\\\\h_(max)=(0^2-58.8^2)/(-2* 9.8)\\\\h_(max)= 176.4\ m`

Hence, this is the required solution .