Answer:
Explanation:
An eigenvalue of n Ă— n is a function of a scalar
considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =
Suppose the matrix
![A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/xber0pg8auhszmbmhhdi27g4o3tx9v4k77.png)
Thus, the equation of the determinant (A -
1) = 0
This implies that:
![\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0](https://img.qammunity.org/2021/formulas/mathematics/college/dnu8c5j5oh2s8uyphpk9mm4dukuu25h8w8.png)



Hence, the eigenvalues of the equation are

Also, the eigenvalues can be said to be complex numbers.