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Fright Night will be a bit different this year. Virtual tickets will cost 10 dollars for adults (a) and 5 dollars for kids(k). Write an algebraic expression that could describe how much you would have to pay for 3 adults and 7 kids?

User Pkr
by
3.8k points

2 Answers

3 votes

Answer:

(10 x a) + (5 x k)

Explanation:

If you were to solve this problem, this would be the process:

First, we need to plug in our values.

(10 x 3) + (5 x 7)

Next, we solve the multiplication.

30 + 35

Finally, the add the two remaining terms to get the total cost for both kid and adult tickets.

$65 would be the final answer.

User Derwyn
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4.0k points
5 votes

Answer:

10a+7k=c

10(3)+7(7)=79

Explanation:

you substitute 3 for a because there are 3 adults.

then you substitute 7 for k because there are 7 kids.

you solve the equation and get 79 the you substitute 79 for c because that is the cost for 3 adults and 7 kids.

User Gkatzioura
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3.3k points