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What is the slope of a line parallel to the line containing (-6,1) and (3,-2)

1 Answer

5 votes

Answer:


m = -(3)/(9)

Explanation:

Use the following formula:

slope:
m = (y_(2) - y_(1))/(x_(2) - x_(1))

Let:


(x_(1) , y_(1)) = (-6 , 1)\\ (x_(2) , y_ {2}) = (3 , -2)\\

Plug in the corresponding numbers to the corresponding variables:


m = (-2 - 1)/(3 - (-6))\\\\m = (-3)/(3 + 6)\\\\m = (-3)/(9)


m = -(3)/(9) is your answer.

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User Pierre Roudaut
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