Question

A certain field is a rectangle with a perimeter of

846
feet. The length is
159
feet more than the width. Find the width and length of the rectangular field.

Answer 1

Width = 132 feet, Length = 291 feet

Explanation:

perimeter (P) = 846

let width(W) = x

length(L) = 159 feet more than width = 159 + W= 159 + x

P of a rectangle = 2*(L + W)

846 = 2*((159 + x) + x)

divide both side by 2

423 = (159 + x) + x

423 = 159 + 2x

rearranging

2x + 159 = 423

2x = 423 -159

2x = 264

divide both sides by 2

x = 132 feet

recall W = x and L = 159 + x

W = 132 feet

L = 159 + 132 = 291 feet