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Solve the equation algebraically. x^2-7x-1/7=0

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1 Answer

4 votes

Answer:


x1=(49+√(2429))/(14) \\x2=(49-√(2429))/(14) \\

Explanation:


x^2-7x-(1)/(7) =0\\7x^2-49x-1=0\\D=b^2-4ac=(-49)^2-4*7*(-1)=2429\\x1=(49+√(2429) )/(14) \\x2=(49-√(2429) )/(14) \\