Question

A rope is used to pull a 4.0 kg bucket of water upwards out of a deep well with an applied force 45 N. If starting from rest, what speed will the bucket have after experiencing this force for 2 seconds?

Answer 1

v = 22.5 m/s

Step-by-step explanation:

The speed of the bucket can be found using the following equation:

`V_(f) = V_(0) + at`

Where:

`V_(f)`: is the final speed =?

`V_(0)`: is the initial speed = 0 (starts from rest)

a: is the acceleration

t: is the time = 2 s

We need to find the acceleration, it can be found as follows:

`F = ma`

Where:

F: is the force = 45 N

m: is the mass = 4.0 kg

`a = (F)/(m) = (45 N)/(4.0 kg) = 11.25 m/s^(2)`

Now, the speed is:

`V_(f) = V_(0) + at = 11.25 m/s^(2)*2 s = 22.5 m/s`

Therefore, the speed that the bucket will have is 22.5 m/s.

I hope it helps you!