Answer:
lim(x---->0) = -5
Explanation:
first: sin(x-π/2)= -cosx
so the equation will be :
lim(x---->0) = [-6cos(ax)-1}/cosx
solve :
lim(x---->0) = [-(6cos(a(0))-1}/cos(0)
cos0=1
lim(x---->0)=(-(6(1)-1)/1
lim(x---->0)=-6+1/1
lim(x---->0)=-5
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