152k views
2 votes
The sum
as three consicutive
multplies of 11 is
363
there eltiples.​

User FeignMan
by
6.6k points

1 Answer

5 votes

Answer:

Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

User Coglialoro
by
6.6k points
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