Question

Physics question URGENT PLEASE!!!

Answer 1

`\left(95(\rm gal)/(\rm min)\right)\left((231)/(1.00)\frac{\mathrm{in}^3}{\rm gal}\right)\left((1.0)/(12)(\rm ft)/(\rm in)\right)^3\left((1.0)/(60)(\rm min)/(\rm s)\right)\approx0.211661\frac{\mathrm{ft}^3}{\rm s}`

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.