Question

What mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid?

Answer 1

Given :

2.5 mole of Sulfuric acid
`( H_2SO_4 )` .

To Find :

Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid

Solution :

Let us assume volume of water be 1 L .

Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .

So , for 2.5 mole sulfuric acid required 5 mole of NaOH .

Moles of NaOH ,

`n=M* Volume \\\\n=5* 1=5\ moles`

Molecular mass of NaOH , M.M = 58.44 g/mol .

Mass of 5 moles of NaOH :

`m=5* 58.44\ g\\\\m=292.2\ g`

Hence , this is the required solution .