What is the temperature of 0.500 moles of helium that occupies a volume of 15.0 L at a pressure of 1.6 atm?

asked Jul 22, 2021 102k views

1 vote

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5 votes

Answer:

600K

Step-by-step explanation:

PV=nRT

T=PV/nR

= 1.6atm* 15.0L/ 0.5mol*0.0821LatmK^-1mol^-1

=600K

BonyT answered Jul 28, 2021

by BonyT

4.4k points

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