Question

A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which to reduce its speed to 11.3 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive).

Answer 1

The value is
`a =  -3.7 \  m/s^2`

Step-by-step explanation:

From the question we are told that

The landing speed is
`u =  71.9 \  m/s`

The distance traveled is
`d =  675 \  m`

The velocity it is reduced to is
`v  =  11.3 \  m/s`

Generally the average acceleration is mathematically represented as

`a =  ( v^2  -  u^2 )/( 2 * d )`

=>
`a =  ( 11.3^2 - 71.9^2 )/( 2 * 675 )`

=>
`a =  -3.7 \  m/s^2`