Question

A solid, insulating sphere of radius 40.0 cm has positive charge distributed uniformly throughout its volume. The electric field at a distance of 80.0 cm from the center of the sphere is 6.00 N/C. What is the electric field at a distance of 20.0 cm from the center of the sphere (in N/C)

Answer 1

The correct answer to the following question will be "12.0 N/C".

Step-by-step explanation:

As we know,

Charged from the inside of the sphere throughout consideration of the electrical field or inside sphere.

⇒
`E_0=(KQ)/(r_0^(2))`

Now,

⇒
`Q=(E_0r_0^(2))/(k)`

On putting the values in the above formula, we get

⇒
`=(6.00* 80.0)/(9* 10^9)((10^(-2))/(2))^2`

⇒
`=4.267* 10^(-10) \ C`

Electric field within the sphere at that same distance of 20.0 cm from either the core.

⇒
`E_i=(kQr_i)/(R^3)`

On putting the values, we get

⇒
`=((9* 10^9)(4.267* 10^(-10))(20.0))/((80.0)^3((10^(-2))/(1) )^2)`

⇒
`=12.0 \ N/C`