Question

It took 73.2 J of heat to raise the temperature of 10.0g of a substance 8.58°C. What is the

specific heat of the substance?

Answer 1

`\boxed{\sf Specific \ heat \ of \ the \ substance \ (c) = 0.85 \: J/g \degree C }`

Given:

Mass (m) = 10.0 g

Rise in temperature (∆T) = 8.58°C

Energy required (Q) = 73.2 J

To Find:

Specific heat of the substance (c)

Step-by-step explanation:

Specific heat (c) of a substance is the energy required to raise the temperature of one gram of the substance by one degree Celsius.

Formula of specific heat is given as:

`\boxed{ \bold{c = (Q)/(m\Delta T)}}`

By substituting value of Q, m & ∆T in the formula we get:

`\sf \implies c = (73.2)/(10 * 8.58) \\ \\ \sf \implies c = (73.2)/(85.8) \\ \\ \sf \implies c = 0.85 \: J/g \degree C`