Question

Find two numbers a and b such that a+b=0 and ab=36

Answer 1

b = 6i then a = -6i

b = -6i then a = 6i

Explanation:

a+b=0

ab=36

a = -b

a(b) = 36

-b * b = 36

- b^2 = 36

b^2 = -36

Take the square root of each side

sqrt(b^2) = sqrt(-36)

b =± 6i

a = - (± 6i)

so b = 6i then a = -6i

b = -6i then a = 6i