Question

It was once recorded that a Jaguar

left skid marks that were 290 min
length. Assuming that the Jaguar
skidded to a stop with a constant
acceleration of -8.90 m/s2,
determine the speed of the Jaguar
before it began to skid.

Answer 1

To determine the speed of the Jaguar before it began to skid, use the equation of motion and solve for the initial velocity.

Step-by-step explanation:

To determine the speed of the Jaguar before it began to skid, we can use the equation of motion: v^2 = u^2 + 2as

Where:
v = final velocity (0 m/s since it comes to a stop)
u = initial velocity (we need to find this)
a = acceleration (-8.90 m/s^2)
s = displacement (290 m)

By substituting the given values into the equation and solving for u, we get:
u^2 = v^2 - 2as
u^2 = 0 - 2(-8.90)(290)
u = sqrt(2*(-8.90)(290))
u ≈ 42.29 m/s

Therefore, the speed of the Jaguar before it began to skid was approximately 42.29 m/s.

Answer 2

71.85 m/s

Step-by-step explanation:

Given the following :

Length of skid marks left by jaguar (s) = 290 m

Skidding Acceleration (a) = - 8.90m/s²

Final velocity of jaguar (v) = 0

Speed of Jaguar before it Began to skid =?

Hence, initial speed of jaguar could be obtained using the formula :

v² = u² + 2as

Where

v = final speed of jaguar ; u = initial speed of jaguar(before it Began to skid) ; a = acceleration of jaguar ; s = distance /length of skid marks left by jaguar

0² = u² + (2 × (-8.90) × 290)

0 = u² + (-5,162)

u² = 5162

Take the square root of both sides

u = √5162

u = 71.847 m/s

u = 71.85m/s