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If DF=10x-2, DE=5x-8 and EF=4x-3, find the value of x and the measure of DE
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If DF=10x-2, DE=5x-8 and EF=4x-3, find the value of x and the measure of DE

User Andrew Brooke
by
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1 Answer

4 votes

Answer:

DE=37

Explanation:

DE+EF=DF

(5x-8)+(4x-3)=10x-2

9x-11=10x-2

x=9

5(9)-8=37

User Timothee
by
5.8k points
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