Question

The position vector of a and b are 2i-j+4k and I+3j+k then magnitude of vector ab is​

Answer 1

The magnitude of vector ab |M| = √26

Explanation:

Mathematically, the magnitude of the position vectors is the distance between the two position vectors.

So in this case;

|M| = √{(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}

From the question;

(x1,y1,z1) = (2,-1,4)

(x2,y2,z2) = (1,3,1)

Substituting these values, we have

M = √(1-2)^2 + (3-(-1))^2 +(1-4)^2

M = √(1 + 16 + 9

M = √26