Question

Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).

midpoint =( ? , ?) ​

Answer 1

`\bigl((3)/(2),-5\bigr)`

or in decimal form

`(1.5,-5)`

Explanation:

The midpoint of the line with endpoints
`(x_1,y_1)` and
`(x_2,y_2)` is
`\bigl((x_1+x_2)/(2),(y_1+y_2)/(2)\bigr)`. just take the average between the points

so given the points (1,0) and (2,-10)

`x_1=1`

`y_1=0`

`x_2=2`

`y_2=-10`

the midpoint is found as follows:

`\bigl((x_1+x_2)/(2),(y_1+y_2)/(2)\bigr)`

`\bigl((1+2)/(2),(0-10)/(2)\bigr)`

`\bigl((3)/(2),(-10)/(2)\bigr)`

`\bigl((3)/(2),-5\bigr)`

or in decimal form

`(1.5,-5)`