Answer:
D
Explanation:
So we have the equation:
![x^2-6x+58=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/kl1y1jhbz24idgwb7mh999ga03ybtrviao.png)
And we want to solve for x.
We can solve it by completing the square.
First, subtract 58 from both sides:
![x^2-6x=-58](https://img.qammunity.org/2021/formulas/mathematics/high-school/oiiq0q30eohocahcsm2hi7cn1alu1vr34b.png)
Divide the b term by 2 and square it:
![(-6)/2=-3\\(-3)^2=9](https://img.qammunity.org/2021/formulas/mathematics/high-school/zhcx7okrocimvc376dgv5ey759hquv830r.png)
So, add 9 to both sides:
![(x^2-6x+9)=-58+9](https://img.qammunity.org/2021/formulas/mathematics/high-school/wzsp4xfeizdq41g9074gwbpzzdan0rsq0x.png)
On the left, the perfect square trinomial pattern. Add on the right. So:
![(x-3)^2=-49](https://img.qammunity.org/2021/formulas/mathematics/high-school/sq708h4ry32jhlyz2xoyowpnpepqnslzj2.png)
Take the square root of both sides:
![x-3=\pm √(-49)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ulszetda0kf7j09uy4lfczmndpli9fnyvn.png)
The square root of -49 is 7i:
![x-3=\pm 7i](https://img.qammunity.org/2021/formulas/mathematics/high-school/yz8lfxd52w44a84l4p5ega9m2pgk8oqxr8.png)
Add 3 to both sides:
![x=3\pm 7i](https://img.qammunity.org/2021/formulas/mathematics/high-school/o7oubntwmk01a6yotgiqlvzaluofrs07n7.png)
So, our answer is D.
And we're done!