Question

Find the equation of a line that contains the points (−2,3) and (0,8). Write the equation in slope-intercept form, using fractions when required.

Answer 1

y = 5/2 x + 8

Step-by-step explanation: Find the slope of the line

y - y so 8 - 3 = 5 = 5/2 is the slope

x- x 0 - -2 0 + 2

The y-intercept is where the line crosses the y axis or (0, 8) where x is 0 and y is b

y = mx + b

m = slope

b = y-intercept (where x = 0)

(x, y) are coordinate points on the line

So, y = 5/2x + 8

Answer 2

Hey there! I'm happy to help!

First we need to find the slope, which is the incline of the line. To do this, you divide the difference of the y values by the difference of the the x values.

3-8=-5

-2-0=-2

-5/-2=5/2

To find the y-intercept, you want to find where the line hits the y-axis. Well, the point (0,8) tells us that the y-intercept is 8. The y-axis is where x=0, so our y-intercept is 8.

Slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.

So....

y=5/2x+8.

Have a wonderful day! :D