52,282 views
43 votes
43 votes
The are adding a new room to their house. The room will be a cube with volume 6859 ft. They are going to put in hardwood​ floors, and the contractor charges ​10$ per square foot. How much will the hardwood floors​ cost?

User Maldus
by
2.9k points

1 Answer

22 votes
22 votes

Answer:

3610 dollars

Explanation:

Remark

If you take the Cube Root of the volume, that will give you the length of an edge of the cube. If you square the edge, you get the area of one of the faces of the cube.

The Cost = the Area of 1 face * 10 dollars. is the answer.

Given

Volume = 6859 cubic feet

Cost per square foot = 10 dollars.

Solution

V = 6859 feet^3 Take the cube root of both sides

Edge = ∛V

Edge = ∛V = ∛6859

Edge = 19 feet exactly.

Area of the floor = s^2

Area of the floor = 19^2

Area of the floor = 361 square feet

Cost = 10 * 361 = $3610

User Noisygecko
by
2.5k points