Question

A particle moves on a straight line and cover a displacement x metres in time t seconds. If the displacement is in form of equation given below. Find its acceleration after 2 seconds. x = 5t^3 - t^2 + 1

Answer 1

58 m / s²

Explanation:

The rate of change of displacement is velocity v

The rate of change of velocity is acceleration a , thus

v =
`(dx)/(dt)` = 15t² - 2t , then

a =
`(dv)/(dt)` = 30t - 2

After 2 seconds

a = 30(2) - 2 = 60 - 2 = 58 m/ s²