Question

Distance between (-4, -3) (2, 1)

Answer 1

`2√(13)`

Explanation:

`d=\sqrt{(x_(2)-x_(1))^(2)+ (y_(2)-y_(1))^(2)}`

`d=\sqrt{(2--4)^(2)+ (1--3)^(2)}\\\\d=\sqrt{(6)^(2)+ (4)^(2)}\\\\d=√(36+16)\\\\d=√(52)\\\\d=2√(13)`

Answer 2

`\Longrightarrow: \boxed{\sf{2√(13)}}`

Explanation:

Question:

• Find the distance between (-4,-3) (2,1)

To find:

• The distance between (-4,-3) (2,1).

Use the distance formula.

Distance formula:

`\Longrightarrow: \sf{√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)}`

`\sf{y_2=1}\\\\\sf{y_1=(-3)}\\\\\sf{x_2=2}\\\\\sf{x_1=(-4)}`

`\Longrightarrow: \sf{√(\left(2-\left(-4\right)\right)^2+\left(1-\left(-3\right)\right)^2)`

Solve.

`\Longrightarrow: \boxed{\sf{2√(13)}}`

• Therefore, the final answer is 2√13.

I hope this helps, let me know if you have any questions.