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Find cos theta, please help!

Find cos theta, please help!-example-1
User Kaderud
by
5.5k points

2 Answers

3 votes

Answer:

21/29

Explanation:


\cos \theta = (AC)/(AB) = (42)/(58) = (21)/(29) \\

User KJA
by
5.5k points
0 votes

Answer:

21/29

Explanation:

Recall that the cosine ratio is the adjacent side over the hypotenuse.

From the triangle, the adjacent side to angle Θ is 42. The hypotenuse (opposite from the right angle) is 58. Therefore:


\cos(\theta)=adj/hyp

Substitute 42 for the adjacent side and 58 for the hypotenuse:


\cos(\theta)=42/58

Reduce:


\cos(\theta)=21/29

And we're done!

User Asjo
by
5.3k points
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