Answer:
m<NQS = 32°
Explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°