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The density of gold is 19.3 grams per milliliter. What would that be in pounds per cup?

1 Answer

1 vote

Answer:


\rho =10.07(lb)/(cup)

Step-by-step explanation:

Hello,

In this case, given that 1 cup equals 236.588 mL and 1 pound equals 453.6 g, the required density in pounds per cup turns out:


\rho =19.3(19.3g)/(mL)*(1lb)/(453.6g)*(236.588mL)/(1cup)\\ \\\rho =10.07(lb)/(cup)

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User Tomer W
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