Question

A balloon contains 146.0 mL of gas confined at a pressure of 1.30 atm and a temperature of 5.0°C. If the pressure doubles and the temperature decreases to 2.0°C, what will be the volume of the gas in the balloon?

Answer 1

72.2 mL

Step-by-step explanation:

Here values of Volume (V), Pressure (P), and Temperature (T) are given : before and after.

Equating LHS (before) to RHS (after)

• P₁V₁/T₁ = P₂V₂/T₂
• V₂ = P₁V₁T₂/T₁P₂
• V₂ = 1.3 × 146 × 275 / 278 × 2.6
• V₂ = 73 x 275 / 278
• V₂ = 72.2 mL