Question

Using the equation E = mc2, calculate how many joules of energy would be produced by converting 6.8 × 10-6 kg of matter into energy in this fusion reaction. Use c = 3 × 108 m/s.

Answer 1

E = 6.12 × 1011 kg × m2/s2

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Using the formula : E = mc²

Where m = mass = 6.8 × 10^-6 kg

c = speed of light = 3 ×10^8 m/s

The amount of joules of energy that would be produced equals :

Plugging in our values :

E = mc²

E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s

E = (6.8 × 10^-6) kg × 9 × 10^16 m/s

E = 61.2 × 10^(-6 + 16)

E = 61.2 × 10^10 J