Question

What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? round to the nearest tenth

Answer 1

`\rho =0.9g/mL`

Step-by-step explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

`V=11.8mL-4.5mL=7.3 mL`

In such a way, considering the mathematical definition of density, it turns out:

`\rho =(m)/(V)=(6.5g)/(7.3mL)\\ \\\rho =0.89g/mL`

Rounding to the nearest tenth we finally obtain:

`\rho =0.9g/mL`

Regards.