Answer:
![\boxed{ \bold{ \huge{ \boxed{ \sf{72}}}}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/y2x0bp7y6widoo8hlgzbvmf583l8wya8x3.png)
Explanation:
Given data : 68 , 69 , 71 , 71 , 71 , 73 , 74 , 75 , 75 , 78
N ( total number of observation ) = 10
Finding the position of median
![\boxed{ \sf{median = { ((n + 1)/(2) )}^(th \: item) }}](https://img.qammunity.org/2021/formulas/mathematics/high-school/d3zbfe4iatlk9qeef5r78496ez3wj3sjjb.png)
![\dashrightarrow{ \sf{median = { ((10 + 1)/(2) )}^(th \: item)}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/7nu4jmcz4yrskf10icmrzfvbejhpgw48kb.png)
![\dashrightarrow{ \sf{median = {( (11)/(2)) }^(th \: item)} }](https://img.qammunity.org/2021/formulas/mathematics/high-school/rkv4704gcjs3vjc7gpeirs9pumzb8lfcst.png)
![\dashrightarrow{ \sf{ median = {5.5}^(th \: item)}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/2ya1zncnzmpbe8np4br4d949mnlv80r2ud.png)
item is the average of 5 th and 6 th items.
Now, Finding the median
![\dashrightarrow{ \sf{median = \frac{ {5}^(th)item + {6}^(th) item}{2} }}](https://img.qammunity.org/2021/formulas/mathematics/high-school/pez1gypk57i1xlfbqj53k1mg3yi8z1la7w.png)
![\dashrightarrow{ \sf{ (71 + 73)/(2) }}](https://img.qammunity.org/2021/formulas/mathematics/high-school/6s7stnjfhmhtn1hoq71a8ha1cawn6gt1w2.png)
![\dashrightarrow{ \sf{ (144)/(2) }}](https://img.qammunity.org/2021/formulas/mathematics/high-school/smuekigy4a01l2xoq12olgcphur9w6dlv8.png)
![\dashrightarrow{ \sf{72}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/33u8rkmx2gu8y5mheeq4obluzi4mj551bg.png)
Hope I helped!
Best regards! :D