Question

A rectangle length is 5 more than its width. If the premiditer of the rectangle is 66 inches, what is the length of the rectangle

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{19 \: inches}}}}}`

Explanation:

Let the width be 'w'.

Length of a rectangle ( l ) = 5 + w

Perimeter of a rectangle = 66 inches

First, finding the width of a rectangle

`\boxed{ \sf{perimeter \: of \: rectangle = 2(l + w)}}`

`\dashrightarrow{ \sf{66 = 2(5 + w + w)}}`

`\dashrightarrow{ \sf{66 = 2(5 + 2w)}}`

`\dashrightarrow{ \sf{66 = 10 + 4w}}`

`\dashrightarrow{ \sf{10 + 4w = 66}}`

`\dashrightarrow{ \sf{4w = 66 - 10}}`

`\dashrightarrow{ \sf{4w = 56}}`

`\dashrightarrow{ \sf{ (4w)/(4) = (56)/(4) }}`

`\dashrightarrow{ \sf{w = 14 \: inches}}`

Width of a rectangle ( w ) = 14 inches

Now, Substituting / Replacing the value of w in order to find the length of rectangle

`\sf{length = 5 + w}`

`\dashrightarrow{ \sf{length = 5 + 14}}`

`\dashrightarrow{ \sf{19 \: inches}}`

Length of a rectangle = 19 inches

Hope I helped!!

Best regards! :D