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A coin flipped 10 times and the results is recorded. What is the probability of getting at least 8 tails ?

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Answer: 0.0546875

Explanation:

The number of times the coin landing head 8 out of 10 is simply:

C(10, 8)/2^10. At least 8 means, 8 or more. Since the events here are dependent on themselves the answer would be:

[ C(10, 8) + C(10, 9) + C(10, 10) ] / 2^10 = 56/1024 = 0.0546875

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