Question

a man pulls a box with a force of 90.0 N directed along the handle which makes angle of 45 degrees with the ground. find the horizontal and vertical components of this force

Answer 1

The horizontal component of the force, Fₓ = 63.64 N

The vertical component of the force,
`F_y` = 63.64 N

Step-by-step explanation:

Given;

magnitude of the force, F = 90 N

angle between the handle and the ground, θ = 45°

The horizontal component of the force, Fₓ = Fcosθ

Fₓ = 90 x cos45

Fₓ = 63.64 N

The vertical component of the force,
`F_y = Fsin \theta`

`F_y` = 90 sin45

`F_y` = 63.64 N

Therefore, the horizontal and vertical components of the force is 63.64 N.